(7x+1)(2x^2+5x-1)=

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Solution for (7x+1)(2x^2+5x-1)= equation: 


Simplifying
(7x + 1)(2x2 + 5x + -1) = 0

Reorder the terms:
(1 + 7x)(2x2 + 5x + -1) = 0

Reorder the terms:
(1 + 7x)(-1 + 5x + 2x2) = 0

Multiply (1 + 7x) * (-1 + 5x + 2x2)
(1(-1 + 5x + 2x2) + 7x * (-1 + 5x + 2x2)) = 0
((-1 * 1 + 5x * 1 + 2x2 * 1) + 7x * (-1 + 5x + 2x2)) = 0
((-1 + 5x + 2x2) + 7x * (-1 + 5x + 2x2)) = 0
(-1 + 5x + 2x2 + (-1 * 7x + 5x * 7x + 2x2 * 7x)) = 0
(-1 + 5x + 2x2 + (-7x + 35x2 + 14x3)) = 0

Reorder the terms:
(-1 + 5x + -7x + 2x2 + 35x2 + 14x3) = 0

Combine like terms: 5x + -7x = -2x
(-1 + -2x + 2x2 + 35x2 + 14x3) = 0

Combine like terms: 2x2 + 35x2 = 37x2
(-1 + -2x + 37x2 + 14x3) = 0

Solving
-1 + -2x + 37x2 + 14x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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